电路叠加定理经典例题讲解（今日分享二十二）
电路叠加定理经典例题讲解（今日分享二十二）定义：对于线性电路，任何一条支路中的电流，都可以看成是由电路中各个电源(电压源或电流源)分别作用时，在此支路中所产生的电流的代数和。Today Xiaobian brings you today's sharing (twenty two) welcome your visit!Share interests spread happiness increase knowledgeand leave a good legacy!Dear you this is The LearningYard Academy.
分享兴趣，传播快乐，增长见闻，留下美好！
亲爱的您，这里是LearningYard学苑。
今天小编为大家带来今日分享（二十二），欢迎您的访问！
Share interests spread happiness increase knowledge
and leave a good legacy!
Dear you this is The LearningYard Academy.
Today Xiaobian brings you today's sharing (twenty two) welcome your visit!
定义：对于线性电路，任何一条支路中的电流，都可以看成是由电路中各个电源(电压源或电流源)分别作用时，在此支路中所产生的电流的代数和。
Definition: For linear circuits the current in any branch can be regarded as the algebraic sum of the currents generated in this branch when each power source (voltage source or current source) in the circuit acts separately.
用叠加定理计算复杂电路，就是把一个多电源的复杂电路化为几个单电源电路来进行计算。
Using the superposition theorem to calculate a complex circuit is to reduce a complex circuit with multiple power supplies into several single-supply circuits for calculation.
证明过程：在前面的文章中讲过电流的求法可以用支路电流法、等效变换法、节点法等等。
Proof process: In the previous article the method of overcurrent can be found using the branch current method the equivalent transformation method the node method and so on.
在图a中，用支路电流法可以列出以下方程（In Figure A the following equations can be listed using the branch current method:）：
当电路中只有E1工作时电流记为I’（左图）；当电路中只有E2工作室电流记为I”（右图）：
The current is denoted as I' when only E1 is operating in the circuit (left); when only E2 is in the circuit the current is denoted as I' (right):
分析电路：左图中只有电动势E1，R2和R3并联后再跟R1串联；右图中只有电动势E2，R1和R3并联后再跟R2并联。
Analysis circuit: only the electromotive force E1 in the left figure R2 and R3 are connected in parallel and then connected in series with R1; In the figure on the right only the electromotive force E2 R1 and R3 are connected in parallel and then in parallel with R2.
因为只有E1工作时的电流方向与原方向一直；只有E2工作时的电流方向与原方向相反所以可得I1：
Because only E1 is working in the direction of the current is the same as the original direction; Only E2 operates in the opposite direction of the current so I1 can be obtained:
注：
- 所谓电路中只有一个电源单独作用，就是假设将其余电源均除去(将各个理想电压源短接，即其电动势为零；将各个理想电流源开路，即其电流为零)，但是它们的内阻(如果给出的话)仍应计及。
- The so-called only one power supply in the circuit acts alone that is it is assumed that the rest of the power supplies are removed (each ideal voltage source is shorted that is its electromotive force is zero; Each ideal current source is open i.e. its current is zero) but their internal resistance if given should still be taken into account.
- 功率的计算不能用叠加定理。
- The superposition theorem cannot be used for the calculation of power.
参考资料：电工学教材
翻译：谷歌翻译
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